(D^3-2D^2-3D+10)y=x^2+3x+1
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D = 2, –2, 1, –1 are the roots. Hence its solution is y = c. 1 e2x + c. 2 e–2x + c. 3 ex + c. 4 e–x. 3) Solve. 3. 2. 3. 2 ... 6. Solve (D2 – 3D + 2) y = 6 e–3x + sin 2x. Ans.: y = c. 1 ex + c. 2 e2x +. 3. 3. 1. (3cos2 sin2 ). 10. 20 x e x x.
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