Math, asked by annelsharma, 1 year ago

d) 301 302
b) 95 X 105
Q37. Lalit has some chocolates. He distributed these chocolates among 13 children in such a way that he
chocolate to first child, 3 chocolates to second child, 5 chocolates to third and so on. Find the number of
chocolates Lalit had.
938. In the adioining figure, ABCD is a rhombus and ZABD = 50°. Find​

Answers

Answered by noornawazkhan
3

Answer:

it is missing , how much he has given to first child,

but what i get.

1 + 3 + 5 +......so on to 13 students

it is simple arithmetic progression question of sum of numbers

here

Sn = n / 2 { 2a + (n-1) d }

n is number of terms to be added, here 13

a is first term here 1

d is difference between numbers here 2

so

S13 = 13 / 2 { 2x1 + ( 13 - 1 ) 2} = 13 x 13 = 169

Step-by-step explanation:

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