Question

(d) 314 cm(min) ,
If the distance travelled by a body in the second is given by (4 +6n)m, then find the initial velocity and acceleration
of the body respectively.
(a) 3 ms-, 6 m s-2
(b) 7 m s., 4 s 2
(c) 7 m s-, 6 ms?
(d) 7 ms!, 3 ms?
​

Answer 1

Answer:

s

nth

=u+

2

a

(2n−1)

4+6n=u+

2

a

(2n−1)

=(u−

2

a

)+an

a=6m/s

2

u−

2

a

=4

u−3=4

u=7m/s