Question

(d) 320, 420, 180 find HCF by long division​

Answer 1

We divide the bigger number by smaller one. Divide smaller number in step 1 with remainder obtained in step 1. Divide divisor of second step with remainder obtained in step 2. We will continue this process till we get remainder zero and divisor obtained in end is the required

160 = 2³ x 2² x 5

220 = 2² x 5 x 11

340 = 2² x 5 x 17

Answer 2

Answer:

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