Question

D = 38 MM, d = 32 MM, FIND THE CROSS SECTIONAL AREA = ...Sq MM
2 points

Answer 1

Step-by-step explanation:

Cross-sectional area of a circular ring is given by the formula,

A = \pi (R^{2} - r^{2})A=π(R

2

−r

2

) ,

where, R is the outer radius and r is the inner radius.

Here, R = 38mm and r = 32mm

So, A = 3.14 (38^{2} - 32^{2}38

2

−32

2

)

A = 3.14 × (1444 - 1024)

A = 3.14 × 420

A = 1318.8 mm^{2}mm

2

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