D
4.
I and m are two parallel lines intersected by
another pair of parallel lines p and a
(see Fig. 7.19). Show that A ABC SACDA. full solution
Answers
Answered by
3
Answer:
I don't know but you can ask to google or your maths guide PLS MARK ME BRAINLIEST
Answered by
3
Step-by-step explanation:
Solution:-
It is given that p q and l m
To prove:-
Triangles ABC and CDA are similar i.e. ΔABC ΔCDA
Proof:-
Consider the ΔABC and ΔCDA,
(i) BCA = DAC and BAC = DCA Since they are alternate interior angles
(ii) AC = CA as it is the common arm
So, by ASA congruency criterion, triangle ABC triangle CDA.
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