Math, asked by kavesh658, 7 months ago

D
4.
I and m are two parallel lines intersected by
another pair of parallel lines p and a
(see Fig. 7.19). Show that A ABC SACDA. full solution

Answers

Answered by SWM
3

Answer:

I don't know but you can ask to google or your maths guide PLS MARK ME BRAINLIEST

Answered by CommanderBrainly
3

Step-by-step explanation:

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Solution:-

It is given that p q and l m

To prove:-

Triangles ABC and CDA are similar i.e. ΔABC ΔCDA

Proof:-

Consider the ΔABC and ΔCDA,

(i) BCA = DAC and BAC = DCA Since they are alternate interior angles

(ii) AC = CA as it is the common arm

So, by ASA congruency criterion, triangle ABC triangle CDA.

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