D. 40 year (Q 12). 12 men can complete a work in 8 days. 3days after they started the work, 3 more men joined them. In how many days will all of them together can complete the remaining work? A. 3 B. 5 C. 4 D. 7?
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men =8days
1 man = 8*12= 96 days
1 man in 1 day = 1/96 of the work
12 men in 3 days do 3/8 of the work
work remaining =5/8
15 men in 1 day do 15/96 = 5/32 of the work
So 5/8 will take 32/5 x 5/8 = 4 more days ANSWER
12 men - 8 days
12 men - 1 day can do 1/8 th of the work
Theoretically, 1 man in 1 day can do 1/8 * 1/12 th of the work or 1/(12*8) = 1/96
So 15 men in 1 day would do 15*1/96 th of the work = 15/96 = 5/32
12 men in 3 days would have completed 3*1/8 of the work = 3/8
Remainder work = 1–3/8 = 5/8
To complete 5/8 th work, 15 men will take 5/8/5/32 = 5/8 * 32/5 = 4 days
C) 4
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