Question

(D) – 42 m/sec.
3.
What is the initial velocity of an object which travels a distance of 10t? +15+5 along a straight line in timet?​

Answer 1

Answer:

answer positive 15

Step-by-step explanation:

POSITIVE 15

Answer 2

SOLUTION

TO DETERMINE

The initial velocity of an object which travels a distance of

$\sf{10 {t}^{2} + 15t + 5}$

along a straight line in time t

EVALUATION

Let S be the distance covered and V be the velocity of the object at any time t

Then

$\sf{S = 10 {t}^{2} + 15t + 5} \: \: .....(1)$

Then velocity is given by

$\displaystyle \sf{V = \frac{dS}{dt} }$

$\displaystyle \sf{ \implies \: V = \frac{d}{dt} \bigg( 10 {t}^{2} + 15t + 5\bigg) }$

$\displaystyle \sf{ \implies \: V = 20t + 15 }$

Hence the required initial velocity

$= \displaystyle \sf{ V \bigg| _{t =0} }$

$= (20 \times 0) + 15$

$= 15$

Hence the initial velocity = 15 unit

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