Question

D(-5, -1), K (-5,-7), P(-1,-7) find the area of triangle​

Answer 1

Answer:

area is 12

hope it will be correct answer

Answer 2

Answer:

The area of the triangle with the vertices (-5, -1), (-5,-7), P(-1,-7) is 12 unit sq.

Step-by-step explanation:

We know that area of a triangle(Δ) = $\frac{1}{2}$ $\left|\begin{array}{ccc}x_{1} &y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right|$

where (x₁,y₁) = Coordinates of first vertex

(x₂,y₂) = Coordinates of second vertex

(x₃,y₃) = Coordinates of third vertex

Substituting the values here, we get

Δ = $\frac{1}{2}$ $\left|\begin{array}{ccc}-5&-1&1\\-5&-7&1\\-1&-7&1\end{array}\right|$

    = $\frac{1}{2}$ {(-5) [-7 - (-7)] -(-1)[(-5)-(-1)] + 1 [ (-5)(-7) - (-1)(-7)]}

    =  $\frac{1}{2}$ {(-5) [-7 +7] -(-1)[(-5+1)] + 1 [ 35 - 7]}

    = $\frac{1}{2}$ {(-5)*0 -(-1)[-4] + 28}

    = $\frac{1}{2}$ {0 -4 + 28}

    = $\frac{1}{2}$ * 24

    = 12

Therefore, the area of the triangle with the vertices (-5, -1), (-5,-7), P(-1,-7) is 12 unit sq.