Question

D 5] In A ABC, seg Adl segBc. Prove that AB2+CD25 BD²+AC² 2 B A​

Answer 1

Answer:

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Answer 2

In△ADC, ∠ADC=90

∴AC

2=AD

2 +CD

2

(By Pythagoras theorem) (1)

In △DBA, ∠ADB=90

o

∴AB

2=AD

2+BD

2

(By Pythagoras theorem) (2)

Subtracting (1) from (2),

AB

2−AC

2=AD

2+BD

2−AD

2−CD

2

∴AB

2−AC

2=BD

2−CD

2

∴AB

2+CD

2=BD

2+AC

2

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