Question

А
D
5) In trapezium ABCD, side AD || side BC,
diagonals AC and BD intersect at point P.
prove that A(∆APD). AD2
_______ = CB2
A(∆CPB)​

Answer 1

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Step-by-step explanation:

Clearly, △APD∼△CPB

⇒

CP

AP

=

PB

PD

⇒

AC−AP

AP

=

PB

PD

⇒

AP

AC

−1

1

=

PB

PD

⇒

3−1

1

=

PB

PD

∴ DP=

2

1

BP