d=5,s9=75, find a & a9
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Hii friend...........
common difference (d) = 5
S9 = 75
nth term (n) = 9
first term= ?
9th term= ?
so,Sn = n/2[2a+(n-1)d]
75 = 9/2[2a+(9-1)5]
75×2 = 9 [2a+(8)5]
150 = 9 [2a+40]
150 = 18a + 360
150-360 = 18a
-210 = 18a
a = -11.6
Then, a9 = a+8d
= -11.66+8×5
= -11.66+40
=28.4
Thanks
Hope it helps u☆☆
common difference (d) = 5
S9 = 75
nth term (n) = 9
first term= ?
9th term= ?
so,Sn = n/2[2a+(n-1)d]
75 = 9/2[2a+(9-1)5]
75×2 = 9 [2a+(8)5]
150 = 9 [2a+40]
150 = 18a + 360
150-360 = 18a
-210 = 18a
a = -11.6
Then, a9 = a+8d
= -11.66+8×5
= -11.66+40
=28.4
Thanks
Hope it helps u☆☆
prachibansiwal:
s s s Ji international school
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