Question

d) 52 3. Choose the correct representation a) O + 2e0? Oxidation​

Answer 1

Answer:

Solution

verified

Verified by Toppr

At anode : [Sn

2+

(aq) → Sn

4+

(aq)+2e

−

]×5

At cathode : [MnO

4

−

(aq)+8H

+

(aq)+5e

−

→ Mn

2+

(aq)+4H

2

O(l)]×2

Cell reaction :

_____________________________________________________________________

2MnO

4

−

(aq)+5Sn

2+

(aq)+16H

+

(aq)→2Mn

2+

(aq)+5Sn

4+

(aq)+8H

2

O(l)

______________________________________________________________________

E

cell

∘

=E

cathode

∘

−E

anode

∘

=1.51V−0.15V

=1.36V

As cell potential is positive therefore the reaction is product favoured