Question

(d) 6.023 1024 carbon atoms
2. How many molecules are present in 5.23 gm of glucose
(CH 200)?
(a) 1.65 x 1022
(b) 1.75 1022
(c) 1.75 X 1021
(d) None of these

3. What is the weight of 3.01 x 1023 molecules of ammonia?
(a) 17 gm
b) 8.5 gm
(c) 34 gm
(d) None of these
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Answer 1

180 g glucose has = N molecules 5.23 g glucose has = 5.23 x 6.023 x 1023/180 = 1.75 x 1022 molecules