d-6/d(d-2) - 3/d (with working, best answer marked brainliest)
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d-6/d(d-2)-3/d
= d-6/d^2- 2d-3/d
=d-6/(d^3 - 2d^2 - 3)/d
=d-6/d^2 - 2d - 3= 0
=> d - 6= d^2 - 2d - 3
=> d-d^2 +2d= -3 +6
=> 3 d - d^2= 3
=> d(3-d)=3
=> d= 3/3-d
=> d= 1/-d
=> d=d
Idk what I just did.........but it’s probably wrong. Did we have to like make it LHS= RHS as the answer?
Hope this kinda gives you a hint to your answer. Sorry!
= d-6/d^2- 2d-3/d
=d-6/(d^3 - 2d^2 - 3)/d
=d-6/d^2 - 2d - 3= 0
=> d - 6= d^2 - 2d - 3
=> d-d^2 +2d= -3 +6
=> 3 d - d^2= 3
=> d(3-d)=3
=> d= 3/3-d
=> d= 1/-d
=> d=d
Idk what I just did.........but it’s probably wrong. Did we have to like make it LHS= RHS as the answer?
Hope this kinda gives you a hint to your answer. Sorry!
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