Question

D
6, In the adjoining figure, ABCD is a rectangle whose diagonals AC and
BD intersect at 0. If ZAOB = 110°, find the measure of:
(1) ZODA and (ii) ZOCD.
110
A
B
[Hint: ZAOD = (180° - 110°) = 70°.
Since OA = OD, we have ZOAD = ZODA.
ZCOD = 110° (Why?) and OC = OD, SO ZOCD = ZODC.)​

Answer 1

Answer:

I.ZODA = 70°

2.ZCOD =11O°

ZODA=ZCOD

70+X=110

x=110-70

x=40