d) A body starts with a velocity of 3m/s and moves in a straight line with a constant acceleration.If its velocity at the end of 5 seconds is 5.5m/s find the distance travelled in 10 seconds.
Answers
Question:-
A body starts with a velocity of 3m/s and moves in a straight line with a constant acceleration.If its velocity at the end of 5 seconds is 5.5m/s find the distance travelled in 10 seconds.
Required Answer:-
Given,
- Initial velocity of the body is 3m/s
- Final velocity is 5.5m/s in 5 seconds
To Find:-
- Distance travelled by the body in 10 seconds
Solution:-
Here, the body moves in a straight line with a constant acceleration. To find the distance travelled by the body, we have to find the acceleration of the body first.
We know that:-
- v = u + at
Where,
- v = Final velocity
- u = Initial velocity
- a = acceleration
- t = Time
We have:-
- Initial velocity u = 3m/s
- Final velocity v = 5.5m/s
- Time t = 5s
Substituting the values:-
5.5 = 3 + a × 5
=> 5.5 - 3 = 5a
=> 5a = 2.5
=> a = 2.5/5
∴ a = 0.5m/s^(2)
Now, we found the acceleration, let's find out the distance travelled in 10 seconds
We know that:-
- s = ut + (1/2)at^(2)
Where,
- s = Distance
- u = Initial velocity
- a = acceleration
- t = Time
We have:-
- Initial velocity u = 3m/s
- Acceleration a = 0.5m/s^(2)
- Time t = 10s
Substituting the values:-
s = 3×10 + 1/2 × 0.5 × 10^(2)
=> s = 30 + 1/2 × 50
=> s = 30 + 25
∴ s = 35m
Hence the distance travelled by the body in 10 seconds is 35m