Question

d)
A bus is running with a velocity of 60 km/hr. On seeing a child at 11m ahead on
the road, the driver applied brakes and the bus stops at a distance of 10 meter.
Calculate its retardation.
(Ans: -73 89 m/s21​

Answer 1

Explanation:

Given :

Initial Velocity [u] = 60 km/h

We will convert km/h to m/s...

➺ 60 × \dfrac{5}{18}

18

5

➺ \dfrac{50}{3}

3

50

Distance covered[s] = 10 m

Final Velocity [v] = 0 m/s

To find :

Retardation

Formula used :

➺ v² = u² + 2as

➺ 0² = \sf(\dfrac{50}{3})^{2}(

3

50

)

2

+ 2 × a × 10

➺ 0 = \sf\dfrac{2500}{9}

9

2500

+ 20 a

➺ 20 a = \sf\dfrac{- 2500}{9}

9

−2500

➺ a = \sf\dfrac{-125}{9}

9

−125

➺ a = - 13.89 m/s.

.°. Retardation = 13.89 m/s...

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