Question

d. A calorimeter has mass 100 g and
specific heat 0.1 kcal/ kg °C. It
contains 250 gm of liquid at 30 °C
having specific heat of 0.4 kcal/kg
°C. If we drop a piece of ice of mass
10 g at 0 °C, What will be the
temperature of the mixture?





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Answer 1

Answer:

27.5 °C

Explanation:

m1 = 100/1000 = 0.1 kg

m2 = 250/1000 = 0.25 kg

m3 = 10/1000 = 0.01 kg

then, 0.1 * 0.1 * (30 - T) + 0.25 * 0.4 * (30 - T) = 0.01 * 1 * (T - 0)

or, 0.3 - 0.01 T + 3 - 0.1T = 0.01T

or, 3.3 = 0.12 T

or, T = 3.3/0.12 = 27.5 °C