D A current through a coil of self inductance 10mH increases from 0 to 1A in 0.1s.what is the
induced emf of coil.
a) 0.1 V b) 1V c) 10 V d) 0.01 V
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Given : A current through a coil of self inductance 10mH increases from 0 to 1 in 0.1s
To Find : induced emf in the coil
a) 0.1 V b) 1V c) 10 V d) 0.01 V
Solution:
induced emf in the coil = L di/dt
(-ve sign is not taken as -ve sign just show oppose )
di/dt = (1 - 0)/( 0. 1)
= 1/(0.1)
= 10
L = 10 mH = 10 x 10⁻³ H
induced emf in the coil = 10 x 10⁻³ * 10
= 100 /1000
= 1/10
= 0.1 V
induced emf in the coil = 0.1 V
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