Question

d) A hydraulic lift has 2 limbs of areas A and 2A. Force F is applied over limb of area A to lift a heavy car. If distance
moved by piston P1 is x, then distance moved by piston P2 is
1) x
2) 2x
3) x/2
4) 4x​

Answer 1

Answer:

x/2

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Answer 2

Given:

Areas of the two limbs P1 and P2 of the hydraulic lift = A and 2A respectively

The magnitude of force applied on P1 = F

The distance moved by P1 = x

To Find:

The distance moved by piston P2

Solution:

Let the distance moved by piston P2  be y

A hydraulic lift's working is based on Pascal's Law for producing force to lift heavy objects.

According to Pascal's Law, an object immersed in liquid experiences equal pressures on all its surfaces.

In a hydraulic lift, since the volume of fluid pushed down on the left side equals the volume of fluid that is lifted up on the right side

⇒ Volume of P1 = Volume of P2

Since Volume = Length X area

⇒ x . A = y . 2A

or y = x/2

Hence, the distance moved by piston P2 is 3) x/2.