Question

(d) A man is 37 years old and his two sons are 8 years and 3 years old respectively
After how many years will he be twice as old as the sum of the ages of his
sons? ​

Answer 1

Answer:

Answer. Given man's age 37 and his elder son's age is 8, So age difference is ED =37–8 = 29 between the man and his elder son. And his younger son's age is 3, age difference is YD= 37–3 = 34 between the man and his younger son. Thus after (42–37 = ) 5 years he becomes twice as old as the sum of the age of his sons.