Question

D A rectangular sheet is obtained by cutting a hollow cylinder along its height. If the cylinder
height 35 cm and lateral surface area 3500 sq. cm, find the perimeter of the rectangular sheet​

Answer 1

Step-by-step explanation:

Curved surface area of a hollow cylinder =4375cm

2

By cutting it from the height, it becomes a rectangular sheet whose width =35cm

So, the height of cylinder =35cm

And length of sheet =

Height

Area

=

35

4375

=125cm

Hence, perimeter of the sheet =2(l+b)=2×(125+35)=320cm

Answer 2

Answer:

perimeter of obtained is 469.8 cm

Step-by-step explanation:

Given height of the cylinder h = 35 cm

lateral surface of the cylinder = 3500 sq

 lateral surface area of cylinder = $2\pi rh$  = 3500

                                                      $\frac{22}{7} r (35)= 3500$   ( $\pi = \frac{22}{7}$ )

                                                    r = $\frac{3500}{35}$×$\frac{7}{22}$ = 31. 81

( r is the radius of the circle base cylinder )

the cylinder is cut along height then a rectangular sheet is formed

take paper  and fold it as a cylinder by doing this you will observe that the breadth of paper becomes as height of the cylinder and length becomes perimeter of the circle which is at top or base

like that when a cylinder cut along its height, its height becomes as its breadth and length as perimeter of the circular base

there the breadth of the obtained sheet = 35 cm

        length of the obtained sheet = perimeter of circle base

                                                         = $2\pi r$

                                                         =$2\frac{22}{7}$ × 31.81  

                                                         = 199. 9    

   therefore perimeter of the obtained sheet = 2(length × breadth)

                                                                            =2( 234.9)

                                                                            = 469.8