Question

d. An electric iron of 1100 W is
operated for 2 hrs daily. What will
be the electrical consumption
expenses for that in the month of
April? (The electric company
charges Rs 5 per unit of energy).
​

Answer 1

your answer is "330"

Explanation

Energy = 1100W = 1.1Kw

Energy=power*time=1.1(kw)*2(hr)=2.2kwh

Energy used in a day=2.2 unit

Energy used in 30 days= 2.2×30unit = 66unit

Total cost=66×5=330 rs

Answer 2

Answer:

Energy consumed = Power of appliance * Time of work

                               = 1100 W * 2h

                               = 2200 Wh = 2.2 kWh.

Now 1 unit  = 1 kWh

So, 2.2 kWh = 2.2 units

Cost of 2.2 units = 2.2 * 5 = Rs. 11

So, daily cost = Rs. 11

April has 30 days.

So total electrical consumption = 2.2 kWh * 30 = 66 kWh.

Total cost = Rs. 11 * 30 = Rs. 330