Question

d. An electric iron of 1100 W is
operated for 2 hrs daily. What will
be the
the electrical consumption
expenses for that in the month of
April? (The electric company
charges Rs 5 per unit of energy).​

Answer 1

Answer:

Electric power required for working of iron, P=1100W

Duration for which the iron is operated daily =2h=

2×60×60=7200s

Electric energy consumed by iron in 7200s is

E=1100×7200=7920000J

Thus, total energy consumed in the month of April,

E=E×30=7920000×30=237600000J

We know,

1 unit =3.6×10

6

J

Or, 1J=

3.6×10

6

1

unit

Thus,

237600000J=

3.6×1000000

237600000

=66 units

Cost of 1 unit of energy = Rs=5

Thus, total electrical consumption expenses for the month of April 66×5=Rs330

Explanation:

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