Question

d. An electric iron of 1100 W is
operated for 2 hrs daily. What will
be the electrical consumption
expenses for that in the month of
April? (The electric company
charges Rs 5 per unit of energy).​

Answer 1

Step-by-step explanation:

$we \: know \: that \: p = \frac{w}{t} \: where \: p = power \: w = work \: done \: t = time \: respectively \: \\ w = p \times t \\ 1100 \times 60 \times 60 \times 2 = 7920000js - 1 \\ 1unit = 3600000 \\ \frac{7920000}{3600000} = 2.2 \: units \: \\ 2.2 \times 5 = 11 \: ruppees$