Math, asked by sharmilipal5177, 2 months ago

d. An electric iron of 1100 W is
operated for 2 hrs daily. What will
be the electrical consumption
expenses for that in the month of
April? (The electric company
charges Rs 5 per unit of energy).​

Answers

Answered by Samvegthepsycho
1

Step-by-step explanation:

we \: know \: that \: p =  \frac{w}{t} \: where \: p = power \: w = work \: done \: t = time \: respectively \:  \\ w = p \times t \\ 1100  \times 60 \times 60 \times 2 = 7920000js - 1 \\ 1unit  = 3600000 \\  \frac{7920000}{3600000}  = 2.2 \: units \:  \\ 2.2 \times 5 = 11 \: ruppees

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