Question

d. An object thrown vertically upwards
reaches a height of 500 m. What was
its initial velocity? How long will the
object take to come back to the
earth? Assume g = 10 m/s2​

Answer 1

Answer:

v^2 - u^2 = 2as

0 - u^2 =2 × 10 × 500

-u^2 = 10000

u= -100 m/s

v - u = at

( v - u ) / a = t

( 0 - ( -100 ) ) / 10 = t

10 seconds = time

Explanation:

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Answer 2

Answer:

Hey Beautiful!

Good Question dear!

Let the initial velocity = u

final velocity = v

v= 0 m/s

s = 500 m

2gs = v2−u2

2 (-10) 500 = u2

u = 100 m/s

v = u + at

0 = 100 - 10 t

t = 10 s

total time taken = 10 sec.