D
and BE = CD.
(a) Is ABCD ACBE?
(b) is AABC an isosceles triangle?
B
12. In the given figure, BD and CE are altitudes of A ABC
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Given ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal
In ΔADB and ΔACE
∠ADB=∠AEC=90
0
(altitudes BD and CE to sides AC and AB)
BD=CE (Given altitudes are equal)
∠BAD=∠DAB (Common angle )
ΔABD≅ΔACE [by SAS congruence]
So AB=AC
Then triangle ABC is an isosceles triangle
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