D and E are mid points of AB and BC respectively. DF || BC. Prove that DBEF is a parallelogram
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Step-by-step explanation:
proof
in Quad DBEF,
given, D and E are mid pts of AB and BC.
so, acc to mid pt theorem, DE is parallel to AC and half the size of AC
also, DF|| BC and D is the mid pt of AB
so acc to mid pt theorem, F is also the mid pt of AC, DF is parallel to BC and half the size of BC.
So DB=EF and are parallel
& DF=BE and are parallel
So DBEF is a parallelogram..
Hence proved
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