Question

D and E are point on side AB and AC respectivaly of triangle ABC such that triangle are (DBC) triangle are (EBC)​

Answer 1

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10th

Maths

Triangles

Basic Proportionality Theorem (Thales Theorem)

In the figure D, E are poin...

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Asked on December 26, 2019 byAsmita Gore

In the figure D, E are points on the sides AB and AC respectively of △ABC such that area(△DBC)=area(△EBC). Prove that DE || BC.



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ANSWER

Given D and E are point on sides AB and AC respectively of triangle ABC such that  Area(ΔDBC) = Area(ΔEBC).

Given that  Area(ΔDBC) = Area(ΔEBC).

Then the height of triangle DBC and Triangle EBC are the same because both triangles are the same 

Then it possible that both triangle on the same base and between parallel line BC and DE 

Therefore, they will lie between the same parallel lines.

∴BC∥DE [henceproved]

Answer 2

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