D and E are points on sides AB and Ac respectively of ∆ ABC such
that ar (DBC) = ar (EBC). Prove that DElIBC
Xy is a line Parallel to side BC of a triangle ABC.If BEllAc and CFllAB
meet xy at E and F respectively, show that
ar(ABE) = ar (ACF)
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∆ DBC and ∆ EBC are on the same base BC and also having equal areas.
therefore ,they will lie between the same parallel lines.
therefore ,
DE||BC
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