Question

D and E are points on sides AB and Ac respectively of ∆ ABC such
that ar (DBC) = ar (EBC). Prove that DElIBC
Xy is a line Parallel to side BC of a triangle ABC.If BEllAc and CFllAB
meet xy at E and F respectively, show that
ar(ABE) = ar (ACF)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

∆ DBC and ∆ EBC are on the same base BC and also having equal areas.

therefore ,they will lie between the same parallel lines.

therefore ,

DE||BC