D and E are points on the base BC of trianglr ABC such that BD is equal to CE if AB is equal to AC pro e that triangle ABE is congruent to ACD
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Given;D and E are points on the base BC of triangle ABC such that BD=CE,AD=AE and angle ADE=angle AED.
To prove; /_ABE(congruent)/_ACD
Proof;AD=AE (GIVEN)
BD=CE(GIVEN)
ADE=AED(GIVEN)
DAE is a common angle sooo...
add with both
ABD+DAE=AEC+DAE
Therefore,ABE=ACD
So we can conclude with ABE(congruent) ACD
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