Math, asked by jyothirenpatel, 4 months ago

D and E are points on the sides AB and AC of ∆ ABC and DE‖ BC . If AD = 1.5 cm , DB =

3cm and AE = 1 cm, find EC​

Answers

Answered by krisnandumaity008
3

Answer:

DE∣∣BC

⟹∠ADE=∠ABC Corresponding angles

∠AED=∠ACB Corresponding angles

∠A is common to both the triangles.

∴ΔADE∼ΔABC by AAA similarity

AD

AB

=

AE

AC

AD

AB

−1=

AE

AC

−1

AD

BD

=

AE

CE

EC=1×

1.5

3

=2 cm

Answered by darksoul3
9

By using basic proportionality theorem,

AD/DB = AE/EC

1.5/3 = 1/x

3/1.5 = x

x = EC = 2

AC = AE + EC = 1 + 2 = 3 cm.

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