D and e are points on the sides ab and ac respectively of triangle abc such that de parallel bc and divides triangle abc into two parts equal in area find bd upon ab
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As triangle ADE ~ ABC
AD/AB = DE/BC
8/8+12 = DE/BC
8/20 = DE/BC
2/5 = DE/BC
BC = 5/2 DE
AD = 6 cm; BD = 9 cm
AE = 8 cm and CE = 12 cm
Now we have:
AD/BD = 6/9 = 2/3
AE/CE = 8/12 = 2/3
So AD/BD = AE/CE
We know that if a line intersects any two sides of a triangle in equal ratio then the line is parallel to the third side.
DE = BC
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