Question

D and E are points on the sides CA and CB respectively of a triangle ABC right angled at C. Prove that AE² + BD² = AB²+ DE².

Answer 1

In

ACE, by Pythagoras theorem,

In

BCD, by Pythagoras theorem,

From 1 and 2, we get

In

CDE, by Pythagoras theorem,

In

ABC, by Pythagoras theorem,

From 3,4,5 we get

Answer 2

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