D and E are the mid point of the sides AB & AC
respectively of a triangle ABC. If BC = 10 cm find DE
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Step-by-step explanation:
Given: D and E are mid points of AB and BC respectively. DF∥BC
Since, DF∥BC D is mid point of AB
By converse of mid point theorem, F is mid point of AC and DF=21BC (I)
Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,
EF∥AB or EF∥DB
Since, opposite sides are parallel to each other. Hence, DBEF is a parallelogram
Perimeter of parallelogram = 2(BE+BD) (Opposite sides of parallelogram are equal)
Perimeter of parallelogram = 2(BE+21AB) (D is mid point of AB)
Perimeter of parallelogram = 2BE+AB
Perimeter of parallelogram = 2×(8.4)+10
Perimeter of parallelogram = 26.8 cm
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