D and e are the points on sides ab and ac respectively of triangle abc such that area of triangle dbc is equal to area of triangle ebc prove that de parallel to bc
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Given: D and E are points on sides AB and AC respectively of ΔABC and area (ΔDBC) = area (ΔEBC)
Construction: Construct two perpendiculars from points D and E on BC.

We know that Area of Any triangle is 
Since, Area of ΔDBC and ΔEBC are same and the base BC is common for both the triangles
So, the height of ΔDBC  is also equal to the height of ΔBEC 
⇒ h1 = h2
We know if the distance between two lines is equal, then the lines are parallel.
Hence BC || DE.
Construction: Construct two perpendiculars from points D and E on BC.

We know that Area of Any triangle is 
Since, Area of ΔDBC and ΔEBC are same and the base BC is common for both the triangles
So, the height of ΔDBC  is also equal to the height of ΔBEC 
⇒ h1 = h2
We know if the distance between two lines is equal, then the lines are parallel.
Hence BC || DE.
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