D and E are the points on sides CA and CB respectively of a triangle ABC right angled at C. Prove that AEsq.+BDsq.=ABsq.+DEsq.
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Answered by
2
I have used pythagoras theorem in 4 triangles and manipulated the equation to get the results
Hope it helps
Hope it helps
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Answered by
8
ur answer is attached, hope it's help u.....
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