Question

D. Answer the following questions.
1. A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.
2. The sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. what is the time period of the vibration?​

Answer 1

Answer:

1. Time period is defined as the time required to complete one oscillation.

Frequency is defined as the number of oscillations per unit time.

Time = 4 sec.

Time Period = (Time taken) / (Number of Oscillations)

Time Period = (4/40) = 0.1 sec.

Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

2. Frequency = 500 vibrations/second.

Time Period = (Time Taken)/ (Number of Oscillations)

= (1/500) = 0.002 sec.

Answer 2

Answer:

• 500 se 1 divide kiya to 0.002 kaise aya