D, are correct
d) A, C are correct
83.
[ ]
b) 4 m/s
a) 2 m/s
c) zero
d) 8 m/s
The velocity of each object is 2.5 ms before the collision during which they stick together. The
velocity of the combined object after collision will be
Answers
Answered by
1
Answer:
(C) ZERO
Explanation:
m
1
=m
2
=1.5 kg
u
1
=2.5 ms
−1
u
2
=2.5 ms
−1
Total mass of the combined system, M=m
1
+m
2
=2×1.5=3kg
Let the velocity of the combined system after the collision be v
Applying conservation of momentum before and after the collision :
m
1
u
1
−m
2
u
2
=Mv
1.5×2.5−1.5×2.5=3v
⟹v=0
Answered by
2
Answer:
c) zero
Explanation:
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