Physics, asked by captainkandala, 4 months ago

D, are correct
d) A, C are correct
83.
[ ]
b) 4 m/s
a) 2 m/s
c) zero
d) 8 m/s
The velocity of each object is 2.5 ms before the collision during which they stick together. The
velocity of the combined object after collision will be​

Answers

Answered by Soushilya
1

Answer:

(C) ZERO

Explanation:

 m  

1

​  

=m  

2

​  

=1.5 kg                          

                   u  

1

​  

=2.5 ms  

−1

                           

                   u  

2

​  

=2.5 ms  

−1

 

Total mass of the combined system, M=m  

1

​  

+m  

2

​  

=2×1.5=3kg

Let the velocity of the combined system after the collision be v

Applying conservation of momentum before and after the collision :

m  

1

​  

u  

1

​  

−m  

2

​  

u  

2

​  

=Mv

1.5×2.5−1.5×2.5=3v            

⟹v=0

Answered by harshadadure123
2

Answer:

c) zero

Explanation:

please mark as branlist please

Similar questions