Question

d Area of rectangle plot is 880 m² and its
length is 44 m breadth its perimetes-Also
find the cost of fencing it at the rate a
of rupees 5 per meter​

Answer 1

$let \: breadth \: be \: x \\ l \times x = 880 \\ x = \frac{880}{44} \\ x = 20 \: m$

$perimeter = 2(20 + 44) \\ = > 2 \times 64 \\ = > 128 \: m$

$cost \: of \: fencing = 5 \times 128 \\ = > 640$

Answer 2

Step-by-step explanation:

$\sf{hey\:}$ $\sf\cancel{mate\:Here\:}$ $\sf\red{is\:ur\:answer}$

area= 880m ^2

length= 44

breadth= B

then,

area of rectangle = L x B

now,

44 x B = 880

B = 880/44

Breadth= 20 m

Now,

perimeter of rectangle = 2(L+B)

perimeter= 2(44+20)=2 x 64= 128

cost of fencing= 128x 5 = ₹640

No copied content ( original)