d by dx of f(x)
differentiation chapter
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f(x)=sin.^2 (x^3+x^2+x+1)^2
df(x)/dx=2(x^3+x^2+x+1)(3x^2+2x+1)[sin2(x^3+x^2+x+1)^2]
here is answer...... also differentiation of sin sq. x =sin2x
df(x)/dx=2(x^3+x^2+x+1)(3x^2+2x+1)[sin2(x^3+x^2+x+1)^2]
here is answer...... also differentiation of sin sq. x =sin2x
Answered by
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Given:
f(x)=sin²(x³+x²+x+1)
Now, Let(also),
t=(x³+x²+x+1)²
» f(x)=sin²t
To Find:
Solution:
On applying the chain rule, i.e.,
Thus,
And,
Now, On mutliplying both the derivatives:
So, the derivative of f(x) w.r.t x is given by:
» " 2sin[2{(x+1)(x²+1)}²].(x+1).(x²+1).(3x²+2x+1) "
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