D/d=[1-x(y-1)]
plzzz....tell solution
& this eq^n answer is x=D-d/d(y-1)
plzz tell na how to explain this eq^n
plzzz.....this is from chemistry... how to explain this
Answers
Answer:
Given,
(x
2
D
2
+3xD+1)y=
(1−x)
2
1
......(1)
Let, x=e
z
,z=lnx,x>0,
dz
d
≡θ
⇒xD≡θ,x
2
D
2
≡θ(θ−1)
substituting these in equation (1)
(θ(θ−1)+3θ+1)y=
(1−e
z
)
2
1
⇒(θ
2
+2θ+1)y=
(1−e
z
)
2
1
....(2)
The general solution is given by, y=y
c
+y
p
y
c
=c
1
e
−z
+c
2
ze
−z
y
p
=
θ
2
+2θ+1
1
(1−e
z
)
2
1
=
θ+1
1
{
θ+1
1
(1−e
z
)
2
1
}
=
θ+1
1
{e
−z
∫
(1−e
z
)
2
1
e
z
dz}
=
θ+1
1
{
1−e
z
e
−z
}
=e
−z
∫
1−e
z
e
−z
e
z
dz
=−e
−z
ln∣e
−z
−1∣
y
p
=−e
−z
ln∣e
−z
−1∣
∴y=c
1
e
−z
+c
2
ze
−z
−e
−z
ln∣e
−z
−1∣
⇒y=c
1
x
−1
+c
2
(lnx)x
−1
−x
−1
ln∣x
−1
−1∣
Explanation:
please mark me as brainliest
Answer:
α=(n−1)d(D−d)→(1)
α=Degree of dissociation
d=Vapor density
n= no of moles of gaseous product for 1 mole of reactant
Any equation in which the total number of moles on product side =n and on reactant side =1.
A) A⇌nB/2+nC/3
here at reactant side n=1
But product side n=2n+3n=65n=n
B)A⇌nB/3+(2n/3)C
here at reactant side n=1
product side n=2n+32n=66n=n
C)A→(n/2)B+(n/4)C
here at reactant side n=1
But product side n=2n+n=42n=n
D)A⇌(n/2)B+C
here at reactant side n=1
But product side n=