Question

D
(D) Given: AB and CD
are equal chords
of the circle with
centre O.
Prove that: ZAOB = ZDOC
B C​

Answer 1

Answer:

Consider triangle AOB and triangle OCD

OA=OB=OC=OD=radius

∠AOB=∠DOC=70

In △OCD

OD=OC

∠ODC=∠OCD

∠OCD+∠ODC+∠DOC=180

2∠OCD=180 o −70 o

∠OCD=55

o =∠ODC