Question

(d) Divide 64 into two parts such that one part is
3 times the other.​

Answer 1

Answer:

16 and 48

Step-by-step explanation:

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Answer 2

Answer:

$let \: one \: number \: be \: 3x \: and \: other \: be \: x \\ according \: to \: the \: problem \\ 3x + x = 64 \\ 4x = 64 \\ x = 16 \\ hence,\\ one \: number \: is \: 3x = 3 \times 16 = 48 \\ other \: is \: x = 16$

Therefore, 48 and 16 are the right answer.