d divided by dt into sin 2T
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hii.. answer is in attachment
hope this helps !
hope this helps !
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tq so much
Answered by
4
Hey !!!
d/dt = (sin2t )
•°• sin2t = 2sint × cost
d/dt = (2sint cost )
Using product rule of derivative rules
= 2[sint d /dt cost + cost d/dx sint
= 2 [sint (- sint) + cost ( cosx )
= 2 [ - sin²t + cos²t ]
= 2 [ cos²x - sin²x ]
•°• [cos²x - sin²x = cos2x ]
= 2 [ cos2t ]
= 2cos2t ✔ Answer
_________________________
Hope it helps you !!!
@Rajukumar111
d/dt = (sin2t )
•°• sin2t = 2sint × cost
d/dt = (2sint cost )
Using product rule of derivative rules
= 2[sint d /dt cost + cost d/dx sint
= 2 [sint (- sint) + cost ( cosx )
= 2 [ - sin²t + cos²t ]
= 2 [ cos²x - sin²x ]
•°• [cos²x - sin²x = cos2x ]
= 2 [ cos2t ]
= 2cos2t ✔ Answer
_________________________
Hope it helps you !!!
@Rajukumar111
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