Math, asked by adepuramya2004, 10 months ago

d/dx 1/cos [ 4x^3/64-3x/4]​

Answers

Answered by Anonymous
1

Answer:

Hey dear ...

here is your answer...

cos^-1 [(x^3/16)-3/4x]

dy/dx= -1/1+[x^3/16-3/4x]^2×1/16×3x^2-3/4

hope it will help you. ...

if u dont understand then ask me in the comment box.

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