Question

d/dx (3x^5 + 3x^3-5) differentiate​

Answer 1

d/dx=d(3x^2+3x^3-5)/dx

dy/dx=2d3x+9x^2-5/dx

dy/dx=6x+9x^2

Here =-5

its constant

so ans

9x^2+6x

Hope it helps u^_^

Answer 2

HØŁÄ!✌

d/dx = d(3x^5 + 3x^3-5)/dx

dy/dx = 2d3x+ 9d^2-5/dx

dy/dx = 6x + 9x^2

-5 is the constant.

Ans: 9x^2+ 6x