Question

d/dx cos ( ax + b)


Give answer fast plz

Answer 1

Let y= cos(ax+b)
differentiate both sides with respect to x
→dy/dx = d{cos(ax+b)}/dx
→dy/dx = (-sin(ax+b)* d(ax+b)/dx..…...(using chain rule)
→dy/dx= (-sin(ax+b)* (a+0)
→dy/dx = -asin(ax+b).

Answer 2

Answer:

Concept: using derivatives  formulae to answer the question.

Given: d/dx cos ( ax + b)

To find: solve the question.

Step-by-step explanation:

Let y= cos(ax+b)

now, differentiating  both sides w.r.t  x, we will get

$\frac{dy}{dx}$ = $\frac{d{cos(ax+b)}}{dx}$

or, $\frac{dy}{dx}$ = $\frac{(-sin(ax+b)* d(ax+b)}{dx}$       ..…...(using chain rule concept)

or, $\frac{dy}{dx}$= $(-sin(ax+b)* (a\frac{d}{dx}x+0)$

or, $\frac{dy}{dx}$= $(-sin(ax+b)* a$

or, $\frac{dy}{dx}$=$-asin(ax+b)$

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