Math, asked by manojsen973, 3 months ago

d/dx( e^x/x^2 )=x^2( d/dx.e^x)-e^x[(d/dx) (x^2)]/(x^2)^2

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Answered by salmanshaikh02693

Last year the price of petrol was Rs.45 per litre. Recently, the government increased the price of petrol to Rs.50 per litre. The percentage increase in the price of petrol is:

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d/dx( e^x/x^2 )=x^2( d/dx.e^x)-e^x[(d/dx) (x^2)]/(x^2)^2​

Answers

d/dx( e^x/x^2 )=x^2( d/dx.e^x)-e^x[(d/dx) (x^2)]/(x^2)^2